5v^2-26v=54

Solution for 5v^2-26v=54 equation:

5v^2-26v=54

We move all terms to the left:

5v^2-26v-(54)=0

a = 5; b = -26; c = -54;
Δ = b2-4ac
Δ = -262-4·5·(-54)
Δ = 1756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1756}=\sqrt{4*439}=\sqrt{4}*\sqrt{439}=2\sqrt{439}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{439}}{2*5}=\frac{26-2\sqrt{439}}{10}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{439}}{2*5}=\frac{26+2\sqrt{439}}{10}
$